How to write the inverse of 3x+4y=12 in f^-1 (x)?

3x+4y=12

4y=12-3x

y=(12-3x)/4   < This is f(x)



3x+4y=12

3x=12-4y

x=(12-4y)/3

Therefore:

f⁻¹(x)=(12-4x)/3

=[4(3-x)]/3

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