The vertex form of the equation of a parabola is x = 8(y - 1)2 - 15.what is the standard form of the equation?
a: x = 8y^2 - 16y - 7
b. x = 16y^2 - 2y - 16
c. x = 8y^2 - 4y + 32
d. x = 16y^2 - 4y + 32

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

c > -10.55

step-by-step explanation: