X. x 1. solve the system by elimination-
-2x+2y+3z=0
-2x-y+z=-3
2x+3y+3z=5
2.solve using substitution-
x-y-z=-8
-4x+4y+5z=7
2x+2z=4

for any : o

Q1. The answer is x = 1, y = 1, z = 0

(i) -2x+2y+3z=0
(ii) -2x-y+z=-3 
(iii) 2x+3y+3z=5

Sum up the first and the third equation:
(i) -2x+2y+3z=0
(iii) 2x+3y+3z=5

5y + 6z = 5

Sum up the second and the third equation:
(ii) -2x-y+z=-3 
(iii) 2x+3y+3z=5

2y + 4z = 2

(iv) 5y + 6z = 5
(v) 2y + 4z = 2

Divide the fifth equation by 2
(iv) 5y + 6z = 5
(v) y + 2z = 1

Multiple the second equation by -3 and sum the equation
(iv) 5y + 6z = 5
(v) -3y - 6z = -3

2y = 2
y = 2/2 = 1

y + 2z = 1
1 + 2z = 1
2z = 1 - 1
2z = 0
z = 0

-2x-y+z=-3
-2x - 1 + 0 = -3
-2x = -3 + 1
-2x = -2
x = -2/-2 = 1

Q2. The answer is x = -37, y = -84, z = -35

(i) x-y-z=-8 
(ii) -4x+4y+5z=7 
(iii) 2x+2z=4

Divide the third equation by 2 and rewrite z in the term of x:
(iii) x+z=2
z = 2 - x

Substitute z from the third equation and express y in the term of x:
x-y-(2-x)=-8 
x - y - 2 + x = 8
2x - y = 10
y = 2x - 10

Substitute z from the third equation and y from the first equation into the second equation:
-4x + 4y + 5z = 7 
-4x + 4(2x - 10) + 5(2 - x) = 7
-4x + 8x - 40 + 10 - 5x = 7
-x -30 = 7
-x = 30 + 7
x = -37
y = 2x - 10 = 2*(-37) - 10 = -74 - 10 = -84
z = 2 - x = 2 - 37 = -35