How do i solve this problem 16x^2 + 1 =8x using this quadractic x=-b+ square root b-4ac /2a

show work so i can better see

16x² + 1 = 8x   First, make this a quadratic equation. Subtract 8x from both sides
16x² -8x + 1 = 0   Now, since ax² + bx + c = 0 is quadratic equation form,  a = 16, b                             = -8, and c = 1. Plug those into the quadratic formula.
x =   Plug in your numbers
x =   Simplify the double negative (- (-8))
x =   Simplify (-8)²
x =   Simplify 4(16)(1)
x =   Subtract 64 from 64
x =   Mutiply 2 and 16
x =   Get rid of the 
x =   Simplify
x = 

Minus 8x both sides
16x^2-8x+1=0
for
ax^2+bx+c=0
x=
a=16
b=-8
c=1
x=
x=
x=
x=
x=
x=
x=
x=

Iam guessing c. or d.