John has six bills of paper money in the following denominations $1, $5, $10, $20, $50, and $100. if he selects 3 bills at a time what is the probability of selecting a group that has an average value of at least $26?

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

529 and 531

step-by-step explanation:

4x and 6y

im not sure though