Line df bisects angle edg. find fg. the diagram is not drawn to scale.

we know that

The angle-angle-side Theorem, or AAS, states that if two angles and any side of one triangle are congruent to two angles and any side of another triangle, then the triangles are congruent

In this problem we have

∠EDF=∠FDG

∠DEF=∠DGF

DF is a common side both triangles

so

triangle DEF and triangle DFG are congruent by AAS

Solve for n

Group terms that contain the same variable, and move the constant to the opposite side of the equation

Combine like terms

Divide by both sides

Find the value of FG

substitute the value of n

therefore

the answer is

answer: a

step-by-step explanation:

if xy ~ yz therefore xy would be the same length as yz