Plz
which equation represents this situation?

josé worked 2.5 hours more than william. together, they worked a total of 22 hours. william worked h hours.

h+2.4=22h+2.4=22

h+5=22h+5=22

h+(h+2.5)=22h+(h+2.5)=22

h+(h−2.5)=22

h+(h+2.5)=22

Step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

the answer is "add 2y and y"

step-by-step explanation:

you need to collect the like terms first.