Find the polar coordinates of the point that has rectangular coordinates (-3,3*sqrt of 3) write your answer using degrees. you: )

X = -3
y = 3*sqrt(3)

r = sqrt(x^2 + y^2)
r = sqrt((-3)^2 + (3*sqrt(3))^2)
r = sqrt(9+27)
r = sqrt(36)
r = 6

theta = arctan(y/x)
theta = arctan(3sqrt(3)/(-3))
theta = arctan(-sqrt(3))
theta = -60 degrees which is coterminal to 300 degrees

So the polar form is (r,theta) = (6, 300)

The expressions would be 0.25a

Where are the functions?