What is the sum of the last four terms 97+99+101++121?

Sum of last four term is 472.

Step-by-step explanation:

Given : 97+99+101++121.

To find : what is the sum of the last four terms .

Solution : We have given that  97+99+101++121.

Common difference =  second term - first term

Common difference = 99 - 97 =  2

Then , fourth term 101 + 2 = 103

Fifth term 103 + 2 = 105

Sixth term  105 + 2 = 107

107 + 2 = 109

109 + 2 = 111

111+2 = 113

113 + 2 = 115

115 + 2 = 117

117 + 2 = 119

119 +2 = 121

Then last four terms are 115 ,  117, 119, 121.

Then,  S = 115 + 117 + 119 +121

S = 472

Therefore, Sum of last four term is 472.

chad should not have included the values (1, 2) and (3, 6) because that would mean he only had half a healing card.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!