"calculate cos theta to two decimal places. (use the pic attached ! )

a. 0.61

b. 1.44

c. 0.72

d. 0.43

Let
T = theta
Use the Law of Cosines to get
c^2 = a^2+b^2 - 2ab*cos(T)
7^2 = 10^2+8^2 - 2*10*8*cos(T)
49  = 164 - 160*cos(T)
-160cos(T) = 49-164
-160cos(T) = -115
cos(T) = -115/(-160)
cos(T) = 23/32
cos(T) = 0.71875 which rounds to 0.72

The final answer is C) 0.72

Let teh greek symbol theta be equal to x. since the triangle is scalene, then apply law of cosine.

a2=b2 + c2 - 2cosx
let a = 7, b = 8 and c = 10

7^2 = 8^2 + 10^2 - 2(8)(10)cosx
cosx = 23/32 or 0.72
x = 44.05 degrees
 
the answer is letter C

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!