Find an equation of the tangent line to the curve
xey + yex = 5

I got:

y′=(−ye^−x−e^y)/xe^y+e^x
then plugged in x and y and got slope of (-5-e^5)
and ended with equation of y=(-5-e^5)x+5

I'm not sure with my solution though i hope this might help you.

I hope my answer has come to your help. Have a nice day ahead and may God bless you always!