Using the side lengths of △pqr and △stu, which angle has a sine ratio of 4/5?

a. p
b. q
c. t
d. u

Given the two triangles, and the sine ratio formula is equal to:

Sin(x) = O/H

Where x is one angle of the triangle

O is the opposite side of the angle x

H is the hypotenuse of the triangle

To solve this we have to fine O/H = 4/5

So the answer is

Sin (P) = 16/20 = 4/5

So angle P has the sine ratio of 4/5

step-by-step explanation:

you divide the denominator by the numerator on both sides and if the quotients are equal then the fractions are equivalent

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