What are the values of x that satisfy the equation x ^2 +4x+3=0

"finding values that satisfy the equation" is just another way of asking you to find the zeroes of the equation. you can find the zeroes/values by factoring:

x² + 4x + 3 = 0  ... factor by trial and error, finding factors of 3 that add up to 4. try 3 and 1.
(x + 1)(x + 3) = 0  ... the next step is to set both of these factors to zero
x + 1 = 0 ... subtract 1 ... x = -1
x + 3 = 0 ... subtract 3 ... x = -3

so the values that satisfy this equation are -1 and -3.

Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*