Three salesmen work for the same company, selling the same product. and, although they are all paid on a weekly basis, each salesman earns his paycheck differently. salesman a works strictly on commission. he earns $65 per sale, with a maximum weekly commission of $1,300. salesman b earns a weekly base salary of $300, plus a commission of $40 per sale. there are no limits on the amount of commission he can earn. salesman c does not earn any commission. his weekly salary is $900. suppose salesmen a and b have the same number of sales and earn the same amount in week 4 of this month. how many sales must they both have had?

12 sales

Step-by-step explanation:

Let x represent the number of sales each man had.

For Salesman A, he earns $65 per sale; this is 65x.

For Salesman B, he earns $40 per sale; this is 40x.  We also add to this his weekly salary of $300; this gives us 40x+300.

Since their pay was equal, set the two expressions equal:

65x = 40x+300

Subtract 40x from each side:

65x-40x = 40x+300-40x

25x = 300

Divide both sides by 25:

25x/25 = 300/25

x = 12

answer: 25.4 units

step-by-step explanation: radius = 12.7 units

diameter = twice the radius

diameter = 12.7 x 2

= 25.4

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!