Which quadratic function has a leading coefficient of 2 and a constant term of –3?

f(x) = 2x3 – 3
f(x) = –3x2 – 3x + 2
f(x) = –3x3 + 2
f(x) = 2x2 + 3x – 3

The answer is f(x) = 2x2 + 3x – 3

f(x) = ax² + bx + c
a - the leading coefficient
c - the constant term

We are looking for a = 2, c = -3

Through the process of elimination:
The first (f(x) = 2x3 – 3) and the third choice (f(x) = –3x3 + 2) have x³ so these are not quadratic function.

In the function: f(x) = –3x2 – 3x + 2
a = -3
c = 2

In the function: f(x) = 2x2 + 3x – 3
a = 2
c = -3

We need the pictures of the graphs

Answercounterclockwise rotation about the origin by 180 degrees followed by reflection about the y-axisexplanationthe given figure has verticesrecall that for counterclockwise rotation about the origin, when we rotate figure pqrs counterclockwise through an angle of 180° about the origin, the coordinates will becomenext, we reflect in the y-axis by negating the x-coordinates of the resulting figure to obtain,therefore the correct answer is c