Show that sec^2x+csc^2x=sec^2xcsc^2x

Sec^2x+csc^2x=sec^2xcsc^2x
Divide both sides by csc^2x
sec^2x+(csc^2x/csc^2x)=sec^2xcsc^2x/csc^2x
sec^2x=sec^2x
Divide both sides by sec^2x
0=0 which is a true statement.

Hope this helps :)

You might know that sec²(x) - tan²(x) = 1. If we solve for sec²(x), then we obtain: 

sec²(x) = 1 + tan²(x) 

Then, 

csc²(x)(1 + tan²(x)) 
==> csc²(x) + csc²(x)tan²(x) 
==> csc²(x) + 1/sin²(x) * sin²(x)/cos²(x) 
==> csc²(x) + 1/cos²(x) 
==> csc²(x) + sec²(x) 
==> RHS 

I hope this helps!

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!

Jim has run 5/6 of a mile so far. i hope that answers your question! good luck : )