The rhombus has vertices k(a, 0), m(a, b), and n(0, c). which of the following could be coordinates of l?

Answer with explanation:

The Vertices of Rhombus K L MN are ,  K(a, 0), M(a, b), and N(0, c).

Let Coordinates of Vertices of Point L ,which is one of the vertices among four vertices = (x,y)

As, Diagonals of rhombus bisect each other.

We will use the mid point formula ,to find the vertex of point L.

Mid Point Formula, of line joining two points , (p,q) and (r,s) is

Mid Point of ,K(a,0) and M (a,b) is

Mid Point of L (x,y) and N (0,c) is

As, Diagonal bisect each other,so

Coordinates of vertices of L are =(2 a, b-c)

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)