Miriam buys 24 petunia plants and 40 azalea plants. she wants to plant an equal number of flowers in each row of her garden. each row will contain only one type of flowering plant

part a: determine the greatest number of plants that could be in each row of the garded

part b: how many rows of each type of flour will be im miriams garden?

A. 8

B.   There will be 3 rows of petunia plants and 5 rows of azalea plants in Miriam's garden.

Step-by-step explanation:

Given : Miriam buys 24 petunia plants and 40 azalea plants. She wants to plant an equal number of flowers in each row of her garden.

The greatest number of plants that could be in each row of the garden = greatest common factor of 24 and 40.

Prime factorization of 24 and 40 :-

The greatest common factor of 24 and 40=

Thus , the greatest number of plants that could be in each row of the garden= 8

The number of rows of petunia plants =

The number of rows of azalea plants =

Hence, there will be 3 rows of petunia plants and 5 rows of azalea plants in Miriam's garden.

10% of increase is the final answer! : )

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!