For each item find how many times greater the 2011 cost is than 1955 cost. round your answer to the nearest hundredth.

1955 2011
movie adddmision\ $0.75 \$9.50
regular popcorn \$0.25 \4.25
drink \$0.35 \$2.75

movie addmision regularpopcorn drink

pl now

Movie admission:

In 1955 the price was $0.75 and in 2011 the price was $9.50

then we must solve $9.50/$0.75 = 12.67  

where I already rounded it to the nearest hundredth.

Then, in 2011 the price was 12.67 times bigger than the one in 1955.

Regular popcorn:

In 1955 the price was $0.25 and in 2011 the price was $4.25

then: $4.25/$0.25 = 17

The price in 2011 was 17 bigger than in 1955

Drink:

in 1955 the price was $0.35 and in 2011 the price was $2.75

then: $2.75/$0.35 = 7.86

The price in 2011 was 7.86 times bigger than in 1955.

i am thinking c. sorry if im wrong .

step-by-step explanation:

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation: