The equation of line wx is y = −2x − 5. write an equation of a line perpendicular to line wx in slope-intercept form that contains point (−1, −2).

y = 1 over 2x + 3 over 2
y = negative 1 over 2x + 3 over 2
y = 1 over 2x − 3 over 2
y = − 1 over 2x − 3 over 2

Y = -2x - 5slope here is -2. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign.
So our perpendicular line will have a slope of 1/2.

y = mx + b
slope(m) = 1/2
(-1,-2)...x = -1 and y = -2
now we sub and find b, the y int
-2 = 1/2(-1) + b
-2 = -1/2 + b
-2 + 1/2 = b
-4/2 + 1/2 = b
-3/2 = b

so ur perpendicular equation is : y = 1/2x - 3/2

The answer would be the second choice : )