Someone !
which of the following statements are true about the graph of f(x) = 6(x + 1)2 -9?
check all of the boxes that apply.
the vertex is (1, -9).
the graph opens upward.
the graph is obtained by shifting the graph of f(x) = 6(x + 1)2 up 9 units.
the graph is steeper than the graph of f(x) = x2.
the graph is the same as the graph of f(x) = 6x2 + 12x - 3.

The graph open upward yes because 6>0 positive number
The graph is the same as the graph of f(x)=6x^2+12x-3 yes because you can just expand the binomial 6(x+1)^2 you get 6x^2+12x+6 with -9 outside
it becomes 6x^2+12x-3
The vertex is (1,-9) no the vertex is (-1,-9)
the graph is shifted up 9 unites no it is shifted down 9 units
the graph is steep yes the large a is the steep the parabola if 0<a<1 then the parabola is less steep

Zero is the mid point of the line segment