Can someone check this?
2x^2 + 50 = −20x
2x^2 + 20x + 50 = 0
2(x^2 + 10x + 25) = 0
2(x + 5)(x + 5) = 0
(x + 5)(x + 5) = 0

x + 5 = 0 or x + 5 = 0
x = − 5, x = − 5
the solution set is
{−5}.

Talia grouped the terms and factored out the gcf of the groups of the polynomial 15x2 – 3x – 20x + 4. her work is shown below. (15x2 – 3x) + (–20x + 4) 3x(5x – 1) + 4(–5x + 1) talia noticed that she does not have a common factor. what should she do?