How do you transform the polar equation theta=pi/6 to an equation in rectangular coordinates and identify its shape?

You are given the theta function θ=π/6, suppose that you have a radius of 4, then we have a polar coordinate of (4,π/6). To change into rectangular form, this is also equal to 
x = 4cosπ/6 and y = 4sinπ/6
x = 2√3 and y = 2
(2√3, 2)

$7.50x+$4.50y=midk it's been awhile since i've done one of these