Afireworks display is launched from a platform 10 feet above ground with an initial upward velocity of 70 feet per second. the height of the fireworks above ground after t seconds is given by the equation h = –16t2 + 70t + 10, where h is the height of the fireworks in feet and t is the time in seconds after they are launched. what is the maximum height of the fireworks display, to the nearest foot?
a.
87 feet
b.
174 feet
c.
70 feet
d.
10 feet

87 ft

Step-by-step explanation:

We are given that the height of the fireworks above the ground after t seconds is given by

Initial velocity of firework display=70 m/s

We have to find the maximum height of the fireworks display .

Differentiate w.r.t t

Substitute h'(t)=0

Again differentiate w.r.t t

Hence, height is maximum at t=

Substitute

Then, we get

Hence, the maximum height of the fireworks display=87 ft

87 ft

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