Aquadratic function has a line of symmetry at x = –3 and a zero at 4.

q1: what is the distance from the given zero to the line of symmetry?

q2: what is the other zero of the quadratic function?

Part 1)

Part 2) The other zero is

Step-by-step explanation:

we know that

If the line of symmetry is equal to

then

the quadratic function is a vertical parabola and the x-coordinate of the vertex is

Part 1) What is the distance from the given zero to the line of symmetry?

The distance is equal to the absolute value of the difference of from

Part 2) What is the other zero of the quadratic function?

we know that

In a quadratic function the distance from the zero's to the line of symmetry is equal

so

Subtract from

The other zero is

so a parallelogram is just like a square base times height. multiply 40 and 39 to get 1560 inches.

a triangle is base times height divided by two. so multiply 7.9 and 5 and then divide it by 2 to get 19.75inches.

the kite can be split into two separate triangles and added together to get the total area. 30 x 4 /2 which equals 60. make sure to double it for the two triangles making 120.