Which equation represents the general form a circle with a center at (–2, –3) and a diameter of 8 units?
x2 + y2 + 4x + 6y – 51 = 0
x² + y² – 4x – 6y – 51 = 0
x2 + y2 + 4x + 6y – 3 = 0
x2 + y2 – 4x – 6y – 3 = 0

Equation for a circle of radius r with center at (h,k) is given by

(x - h)^2 + (y-k)^2 = r^2

(x-(-2))^2 + (y-(-3))^2 = 4^2
x^2 + 4x + 4 + y^2 + 6y + 9 = 16
x^2 + 4x + y^2 + 6y - 3 = 0
Rearranging, the answer is
x^2 + y^2 + 4x + 6y - 3 = 0

I'm just guessing, but my answer would c. 0 to 300.

C. i possibility the answer to this