Anumerical pass code is required to open a car door. the pass code is five digits long and uses the digits 0–9. numbers may be repeated in the pass code. how many different pass codes exist

100,000

Step-by-step explanation:

A numerical pass code is required to open a car door.

The pass code is five digits long and uses the digits 0–9.

So, total number of possible digits will be 10

Condition:-

Total number of possible pass code = __×__×__×__×__

For each blank space we have 10 choices to fill because digit repeated. So, every blank space 10 possible digits.

Total number of possible pass code = 10×10×10×10×10

                                                            = 10⁵

                                                            = 100,000

Hence, Total number of pass code form will be 100,000

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

pentagon

step-by-step explanation:

the coordinates   a(5, -2), b(3,-1),c(-4,-4) d(-3,8) and e(-1,4) forms the vertices of the polygon when they are connected in order.

in order to classify that which polygon is it with the given coordinates, first count the number of vertices and then count the number of sides it can make with these vertices.

since, the given coordinates have five vertices, therefore, it will make five sides. moreover, pentagon is regular in nature therefore it will be convex.

now, a polygon with five sides is known as pentagon, therefore, the given polygon is the pentagon.