Identify the conclusion of the following conditional:
a number is divisible by 3 if the sum of the digits of the number is divisible by 3.
a. the number is odd.
b. if the sum of the digits of a number is divisible by 3, then the number is divisible by 3.
c. the number is divisible by 3.
d. the sum of the digits of the number is divisible by 3.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

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step-by-step explanation:

answer: -0.5 would be the most likley outcome

step-by-step explanation: