1. given δqrs (is congruent to) δtuv, qs = 3v + 2 and tv = 7v - 6, find the length of qs and tv. provide a detailed response below, . i was not provided with a picture, unfortunately.

Because ΔQRS is congruent to ΔTUV, the the segments GS and TV are also congruent due to the letter order (Q and T are first and S and V are 3rd.) Since they are congruent QS=TV. So 3v + 2 = 7v - 6

Work: 
3v + 2 = 7v - 6
      +6          +6
3v + 8=7v
-3v       -3v
8 = 4v
4      4
2 = v

3(2) + 2 = GS
6+2 = GS
8 = GS

7(2) - 6 = TV
14-6=TV
8 = TV

Final  8=QS and 8=TV