Mathematics, 20.01.2020 05:31 desiwill01

Aload of bricks is twice as heavy as a load of sticks. the total weight of 4 loads of bricks and 4 loads of sticks is 771 kilograms. what is the total weight of 1 load of bricks and 3 loads of sticks

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Answer from: lunax7x7

The total weight of 1 load of bricks and 3 loads of sticks : $\large{\boxed{321.25\:kg}}}$

Further Explanation

One variable linear equation is an equation that has a variable and the exponent number is one.

Can be stated in the form:

$\large{\boxed{\bold{ax=b}}$

ax + b = c, where a, b, and c are constants, x is a variable

Whereas the two-variable linear equation is a linear equation that has 2 variables and the exponent is one

Can be stated in the form:

$\large{\boxed{\bold{ax+bx=c}}}$

x, y = variable

In the statement of the task:

a load of bricks is twice as heavy as a load of sticks.

If we translate this sentence into equation, :

B = 2S ( B = bricks, S = sticks) ---> equation 1

the total weight of 4 loads of bricks and 4 loads of sticks is 771 kilograms.

If we translate this sentence into equation, :

4B + 4S = 771 kg ---> equation 2

This equation belongs to One variable linear equation because there is two variable = B&S and the exponent number is one

The solution is :

we put equation 1 in equation 2, become :

8S + 4S = 771 kg

12S = 771 kg

$\displaystyle S=\frac{771}{12}$

$\large{\boxed{S=64.25\:kg}}$

from equation 1 :

B = 2 x S

B = 2 x 64.25 kg

B = $\large{\boxed{128.5\:kg}}$

the total weight of 1 load of bricks and 3 loads of sticks

If we translate this sentence into equation,

B + 3S = ?

we enter the values of B and S from the results of the equation above

= 128.5 kg + 3(62.25 kg)

= 128.5 kg + 192.75 kg

= $\large{\boxed{\boxed{\bold{321.25\:kg}}}$

Learn more

the slope-intercept form of the linear equation

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a graph of a linear equation

link

system of linear equations

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Keywords : one variable, linear equation , two variable, bricks, sticks

Aload of bricks is twice as heavy as a load of sticks. the total weight of 4 loads of bricks and 4 l

Answer from: Quest

i can you with this question sweetie!

step-by-step explanation:

Answer from: Quest

x= -3 and $x=\frac{-3+/-3i\sqrt{3} }{2}$

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

$(x^3-a^3)=$ $(x-a)(x^2+ax+a^2)$

where a is the cube root of $a^3$ .

here this is 27 and the cube root of 27 is 3. so we write using the form:

$(x-3)(x^2+(3)x+3^2)\\(x-3)(x^2+3x+9)$ .

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

$x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where a = 1, b=3, and c=9

$x=\frac{-3+/-\sqrt{3^2-4(1)(9)} }{2(1)} \\x=\frac{-3+/-\sqrt{9-36)} }{2} \\x=\frac{-3+/-\sqrt{-27)} }{2}\\x=\frac{-3+/-3i\sqrt{3} }{2}$

this cubic has two complex roots.

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