What is the equation of the line in slope-intercept form that is perpendicular to the line y = 3/4x – 2 and passes through the point (–12, 10)?

Perpenciaular means has slope taht muliptlist so -1
y=mx+b
m=slope
3/4 times what=-1?
-4/3

the equation of a line that passes through tht point (x1,y1) and has  a lsope of m is
y-y1=m(x-x1)
given
(-12,10) and -4/3
y-10=-4/3(x+12)

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0

the value of x is equal to 0.