Solve the compound inequality 3x+12 -9 and 9x-3 33

Solve each seperately

3x+12>-9
minus 12 both sides
3x>-21
divide by 3 both sides
x>-7

9x-3<33
add 3 both sides
9x<36
divide both sides by 9
x<4

so

x>-7 and x<4
-7<x<4
solution is all numbers betwee -7 and 4 not including -7 nor 4

1. 3/6 or 1/22. 1/123. 1/84. 1/105. 2/12 or 1/6