Aplane at 3,800 feet is descending at a rate of 120 feet per minute, and a plane at 520 feet is climbing at a rate of 40 feet per minute. in how many minutes will they be at the same altitude? write a system of equations. then graph the system to determine the solution.

so the basic formula for this d = rt

where d is the distance , r is the speed and t is time

3800 – 120t = 520 + 40t ( this is the altitude of each plane are equal)

Solve for t

T = 20.5 min time it takes for the planes to be at the same altitude

3800 – 120(20.5) = 1340 ft

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.

it is not that hard all u have to do is plot the graph

step-by-step explanation: