The rule ro, 90° • t-1, 1(x, y) is applied to δbcd to produce δb"c"d". point b" of the final image is at (–4, 1).
(–2, –5)
(0, –5)
(2, 3)
(5, 0)
can anyone ? i think it is either (0,-5) or (2,3) but i am not sure whether to rotate clockwise, or counter-clockwise?

The transformation starts with T-1, 1(x, y) and ends with RO, 90° (counter-clockwise).

To find the original point, we work backwards.

We start with RO, -90° (clockwise):

which gives


We then do the reverse of T-1, 1(x, y), which is T1, -1(x, y):

which gives


so the answer is .