The ratio of the length of the corresponding sides of two rectangles is 5: 8. the area of the smaller rectangle is 130 m2. to the nearest whole number, what is the area of the larger rectangle?

Area of the larger rectangle = 332.8 m²

Step-by-step explanation:

Ratio of the corresponding sides of two rectangles is 5 : 8 and the area of smaller rectangle is 130 m²

We have to calculate the area of larger rectangle.

Let length of two rectangles are L and L' and width be W and W'.

Now as given in the question

L/L' = 5/8 and W/W' = 5/8

Therefore ratio of two rectangles = A/A' = (L×W)/(L'×W') = (L/L')×(W/W') = (5/8)×(5/8) = (5/8)²

A/A' = (5/8)² = 130/A'

A' = 130× (8/5)² = (130×64)/25 = 332.8 m²

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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