If a quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors, then which statement would be true?
the figure must be an isosceles trapezoid because it has 2 congruent base angles.
the figure must be a rectangle because all rectangles have exactly 2 lines of symmetry.
the figure must be a rhombus because it has exactly 2 pairs of congruent angles.
the figure must be a square because the diagonals of a square bisect the right angles.
i'm thinking rhombus, is that right?

A quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors.

A trapezoid has diagonals which do not bisect each other as well as they do not bisect the angle.

A rectangle has 2 lines of symmetry but its diagonals even though bisect each other do not bisect the angles.

A square's diagonals do bisect each other as well as the angles, but a square has 4 lines of symmetry,

So a rhombus whose diagonals bisect each other as well as the angles should be the quadrilateral.

So a quadrilateral which has exactly 2 lines of symmetry, and both are angle bisectors, is the rhombus.

Third option or Option C) is the right answer.

she would want to sell 10 full-year subscriptions and at least 9 half-year subscriptions to get a total of at least $300. 

i hope this answer you! if you have any further questions or concerns, feel free to ask! : )

step-by-step explanation:

mark brainliest!

120 seems like the most sensible answer.

step-by-step explanation:

if there is only one topping on all caramel apples and there's 120 of them. then all apples should/will be covered in sprinkles. make sense?