Hey need with some homework my teacher did not explain this very well so could you me answer it and explain how iis done?

3y + 6
= -9
11

y in (-oo:+oo)

(3*y+6)/11 = -9 // + 9

(3*y+6)/11+9 = 0

(3*y+6)/11+(9*11)/11 = 0

3*y+9*11+6 = 0

3*y+105 = 0

(3*y+105)/11 = 0

(3*y+105)/11 = 0 // * 11

3*y+105 = 0

3*y+105 = 0 // - 105

3*y = -105 // : 3

y = -105/3

y = -35

y = -35

(3y+6)/11=-9
times both sides by 11
3y+6=-99
minus 6 both sides
3y=-105
divide both sides by 3
y=-35

2xy/9 is the answer to this problem