The sierpinski triangle is a type of progression where an equilateral triangle has 1/4 of its area removed to create a new shape. a series of these triangles is shown below, starting with an area of 64. if we remove 1/4 of the area what fraction of the area remains?

The Sierpinski Triangle is a type of progression where an equilateral triangle has 1/4 of its area removed to create a new shape.
starting with an area of 64. If we remove 1/4 of the area 
so the removed area = 64* ( 1/4) = 16
remaining area = 64 - 16 = 48

fraction of the remaining area = 48 / 64 = 3/4
or another way 1 - 1/4 = 3/4

The answer to your question is the last one

It’s d for sure i just did also that’s why