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![D:\\3x 0\ and\ x+4 0\\x 0\ and\ x -4\\therefore\ D:x\in(-4;\ \infty)\\------------------\\log(3x)=log2+log(x+4)\ \ \ |use\ loga+logb=log(a\cdot b)\\\\log(3x)=log[2(x+4)]\iff3x=2(x+4)\\\\3x=2x+8\ \ \ \ |subtract\ 2x\ from\ both\ sides\\\\\boxed{x=8\in D}](/tpl/images/0184/1409/d0757.png)
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