Find the dimensions of a rectangle whose perimeter is 16 meters and whose area is 15 square meters.

2(x+y)=16,
x+y=16/2=8
y=8-x
x*y=15
x(8-x)=15
8x-x^2=15
x^2-8x+15=0
x^2-3x-5x+15=0
x(x-3)-5(x-3)=0
(x-3)(x-5)=0
x=3,5
when x=3
y=8-3=5
when x=5
y=8-5=3
length=5 meters
width=3 meters.

If the angles sides are labeled as A,B,C, and D, with A and B opposite from eachother as well as C to D. then angles A and B would have to be equivalent. if the area= 15 (area=LxH) then the dimensions would have to be 3 and 5 because 5 and 3 are the only two whole numbers that make a product of 15. Since A and B would have to be equal to each other then they would be 5 or 3, as well as C and D. added up in total if A= 5 B= 5 C= 3 D=3 (5+5+3+3=16) (perimeter= All sides/faces added)