Mathematics, 25.10.2019 11:43 kortlen4808
Oil is leaking from a tanker at the rate of r(t) = 2000e^(-0.2t) gallons per hour where t is measured in hours. how much oil leaks out of the tanker from the time t = 0 to t = 10
Answers: 3
![\rm R(t) = 2000e^{(-0.2t) }\\\\R(t)=\int\limits^{10}_0{2000. e^{(-0.2t)}} \, dx \\\\R(t)=2000\int\limits^{10}_0{ e^{(-0.2t)}} \, dx \\\\ R(t) = 2000[-e^{(0.2t]}^{10}_0\\\\R(t) = 2000{e^{(-0.2(10-0)}}\\\\R(t) = 2000.{e^{(-0.2\times10)}\\\\R(t) = 2000.[e^{-2}}]\\\\R(t) = 2000\times (0.1357)\\\\R(t) = 270.67](/tpl/images/0345/9633/70fe0.png)
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Oil is leaking from a tanker at the rate of r(t) = 2000e^(-0.2t) gallons per hour where t is measure...
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