Not really understanding how the derivative of y=sin^2(x) is 2cosx*sinx? i know we use the chain rule, but steps would .

when it comes to trigonometric functions and exponentials,
the exponent usually as a matter of notation, goes with the
name of the trig function, and then you put the argument or
parameters ahemm... that's just a notational issue

now, if you were to do as above, so simply group the whole
function in parentheses or brackets, and THEN apply the
exponential, the expression is exactly the same,
but the grouping makes it more conspicuous what the exponent,
is comprising

Is there any commas or anything

That’s what i got when i looked up what the solutions were