Mathematics, 25.08.2019 10:30 alliemeade1

Math
the solutions to 15(2a – 2) = 5(a2 – 1) are:
a = 1, a = –1
a = 5, a = –1
a = 5, a = 1

Answers: 2

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Math
the solutions to 15(2a – 2) = 5(a2 – 1) are:
a = 1, a = –1
a = 5, a = –1

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Math the solutions to 15(2a – 2) = 5(a2 – 1) are: a = 1, a = –1 a = 5, a = –1 a = 5, a = 1

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Math
the solutions to 15(2a – 2) = 5(a2 – 1) are:
a = 1, a = –1
a = 5, a = –1
a = 5, a = 1