Ahome’s value increases at an average rate of 5.5% each year. the current value is $120,000. what function can be used to find the value of the home after x years? f(x) = 120,000(1.055)x f(x) = 120,000(0.055)x f(x) = 120,000(1.055)x f(x) = [(120,000)(1.055)]x

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Step-by-step explanation:

We are given that,

The present value for the home is $120,000 and the rate of interest is 5.5% i.e. 0.055.

As we know that the function for the home is given by,

where P = present value, r = rate of interest, x = number of years.

So, according to the question, we get that,

i.e. .

Hence, we see that the function that represents the value of the home is .

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2