There are given complex numbers
z1=(m-2n-1)+i(5m-4n-6)
z2=(3m-n-6)+i(m-5n-3)
q: find m and n in a way that z1 and z2 to be conjugated complex numbers, then deternime real and imaginary par of z=z1-z2/conjugated z2

Ok... so, we know that both pairs are conjugate of each other,
so.. both are complex solutions, namely, both are a+bi type

what's "a", we dunno, what is "b", we dunno either
but for z1, we know that a = m-2n-1   and b = 5m-4n-6
for z2, a = 3m-n-6 and b=m-5n-3

for those two folks to be conjugate of each other, they'd be
(a+bi)(a-bi)
notice, the "a"s are the same on z1 as well as z2
the "b" are the same also BUT the z2 "b" is negative,
in order to be a conjugate, regardless of that, the "b"s are the same

so, whatever (m-2n-1) is, is the same as (3m-n-6), since a = a
and whatever (5m-4n-6) is, will be the same value, since b =b,
the "a" and "b" in each conjugate, is the same value, thus one can say




and pretty sure you can find "m" from there
once you  have both, substitute in z1 or z2, to get the values for "a" and "b"