Abox contains 4 white balls and 5 red balls. i draw 3 of them out of the box, one at a time, without replacement. what is the probability that the balls i draw alternate between the two colors?

Let A be the probability of drawing a white ball first, then a red one second, and then a white one last.

Let B be the probability of drawing a red ball first, then a white one second, and then a red one last.

So, P(A or B)  = 

[4/9 x 5/8 x 3/7 =  60/504 ] + [ 5/9 x 4/8 x 4/7 = 80/504 ]  =

[60 + 80 ] / 504  = 140/504 =  5/18 = about 27.8%

the correct answer is

c. 4

step-by-step explanation:

the given polynomial is

the degree of the polynomial is the highest exponent which is 4.

the -4 is called the leading coefficient.

this polynomial has only one term so it is a monomial.

the correct answer is option c.

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24