How do i solve using substitute method

When using the substitution method, the easiest way to start off is to make sure you have one equation set to equal either y or x. That would give you:
y=-x+1
-4x+4y=12
Then, you put the equation set to y inside the other equation to get:
-4x+4(-x+1)=12
You would the solve the equation to get:
-4x-4x+4=12
-8x+4=12
-8x=8
x=-1
Now you still have to find the y value. You would now put the x value inside either of the equations and solve it. I chose the first one and got:
2(-1)+2y=2
-2+2y=2
2y=4
y=2
Your answer is (-1,2).

Choose a variable in the first equation to solve for
2x + 2y = 2
2x = 2 - 2y, divide each side by to leaving x on one side
so x = 1 - y

Now plug that in for x in the second equation
-4x + 4 y = 12
-4 (1 - y) + 4y = 12
so -4 + 4y + 4y = 12
then add 4 to each side and combine the y terms
8y = 12 + 4 = 16
8y = 16  divide both sides by 8
so y = 2

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