Point m is the midpoint of segment ab. if am = 50 – 3x and mb = –20 + 4x, find the value of am

 The length of AM is 20 units.

Step-by-step explanation:  We are given that the point M is the midpoint of segment AB, where

AM = 50 – 3x    and    MB = –20 + 4x.

We are to find the length of AM.

Since M is the midpoint of the segment AB, so we must have

Therefore, the value of AM is calculated as follows :

Thus, the length of AM is 20 units.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐