What is the value of h(−3) when h(x)= 6x2 − 2x + 12?
a. −306
b. −36
c. 48
d.72
e. 342

72

Step-by-step explanation:

Parentheses Exponents Multiplication Division Addition Subtraction

h(-3) = 6(-3)^2 - 2(-3) + 12

E h(-3) = 6(9) - 2(-3) + 12

M h(-3) = 54 - (-6) +12

A h(-3) = 66 - (-6)

S h(-3) = 72

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

it is c, trust i got your back lol

step-by-step explanation: