A6.0 cm high elevation block is placed under one end of a 1.0 m long track. find the angle of elevation of the track.

3.4°

Step-by-step explanation:

A 6.0 cm high elevation block is placed under one end of a 1.0 m long track.

Block is 6 cm high. It would stand vertically.

Stand one end of horizontal track 1 m long.

Please see the attachment for graph.

Let the elevation of block is Ф

In ΔABC, ∠B=90°

AB= 6 cm

BC = 1 m

First we change meter to centimeter. 1 m = 100 cm

So, BC = 100 cm

Hence, The elevation of the track is 3.4°

angle q= 92 degree

step-by-step explanation:

the solution is in the picture

when a quadrilateral is inscribed in a circle, the opposite angles are supplement to each other. in other words, the sum of the 2 angle is 180 degree